2x^2+3(2x^2)=119

Solution for 2x^2+3(2x^2)=119 equation:

2x^2+3(2x^2)=119

We move all terms to the left:

2x^2+3(2x^2)-(119)=0

We add all the numbers together, and all the variables

34x^2-119=0

a = 34; b = 0; c = -119;
Δ = b2-4ac
Δ = 02-4·34·(-119)
Δ = 16184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16184}=\sqrt{1156*14}=\sqrt{1156}*\sqrt{14}=34\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-34\sqrt{14}}{2*34}=\frac{0-34\sqrt{14}}{68}
=-\frac{34\sqrt{14}}{68}
=-\frac{\sqrt{14}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+34\sqrt{14}}{2*34}=\frac{0+34\sqrt{14}}{68}
=\frac{34\sqrt{14}}{68}
=\frac{\sqrt{14}}{2}
$